|
Bond |
Bond energy (kJ mol-1) |
|
C-H |
413 |
| O=O |
496 |
| O-H |
463 |
| C=O |
743 |
Suppose we want to break 1 mole
of O-H bonds, we need to put in 463 000 J (463 kJ). When they
reform, we get 463 kJ back as heat. Let us look at how
bonds are rearranged in this reaction:
methane + oxygen
® carbon dioxide +
water
CH4(g) + 2O2(g)
® CO2(g)
+ 2H2O(g)

Let's do an energy audit on what
happens in the reaction:
1. Look at the reactants:
-
There are 4 C-H bonds.
Each one has a bond energy of 413 kJ mol-1. The
total energy in a mole of these bonds is 4 × 413 = 1652 kJ
-
There are 2 O=O bonds.
The total energy in a mole of these bonds is 2 × 496 = 992 kJ
-
Total energy needed to break
these bonds is 1652 + 992 = 2644 kJ
2. Now look at the
products:
-
There are 2 C=O bonds.
The total energy per mole is 2 × 743 = 1486 kJ
-
There are 4 O-H bonds. The
total energy per mole is 4 × 463 = 1852 J
-
The total energy given out is
1486 + 1852 = 3338 kJ.
3. The amount of energy given out
in this exothermic reaction is given by:
energy out = bond energy of the products -
bond energy of the reactants
energy = 3338 - 2644 = 694 kJ mol-1
Chemists have a convention that
says that energy out is negative, so strictly speaking, we
should write -694 kJ mol-1.
We can sum this up as an energy
profile diagram:

You can see that there is quite a
big hump to cross before the reaction happens. We don't
actually have to put this amount of energy in to set methane
burning. A spark will have enough energy to break the bonds of
a few (million) molecules. As they give out heat, more
molecules will be activated, and the reaction propagates. The
way the reaction happens does not affect the total energy per mole.
The effect of a catalyst
is to lower the energy hill (lower the activation energy), making
the rate of reaction faster:
