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Grade A
Kinetic energy is given by the equation:
kinetic energy (J) = 1/2 × mass
(kg) × (speed (m/s))2
In Physics Code:

Suppose we use a force
F to
accelerate an object steadily from zero up to a speed
v.
The kinetic energy is the same as the work done.
Kinetic energy (J) = force (N) ×
distance moved (m) .......Eq 1
Since:
Force (N) = mass (kg) ×
acceleration (m/s2)
we can write:
Force (N) = mass (kg) × [change
in speed (m/s) ÷ time (s)]
In Physics code:
F = m × [(v - 0) ÷
t] = m × v/t
Now:
distance travelled = average
speed × time
In Physics code:
d = [(v - 0) ÷ 2] × t =
1/2 v × t .........Eq 2
Combining equations 1 and 2:
Kinetic energy =
F × d
Ek
= m × v/t × 1/2 v × t
The t terms cancel out to give us:
Ek
= 1/2 mv2 [Boom! Boom!]
The ability to follow this
derivation is the sort of thing that will distinguish the
outstanding student (A*) from the excellent student (A).
Note that we have talked about
speed rather than velocity. The kinetic energy of an object is
the same regardless of direction. We can say this, because
of we have a negative velocity, the kinetic energy will still be
positive, since minus times a minus is a plus.
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